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n^2-6n+5=16^2
We move all terms to the left:
n^2-6n+5-(16^2)=0
We add all the numbers together, and all the variables
n^2-6n-251=0
a = 1; b = -6; c = -251;
Δ = b2-4ac
Δ = -62-4·1·(-251)
Δ = 1040
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1040}=\sqrt{16*65}=\sqrt{16}*\sqrt{65}=4\sqrt{65}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-4\sqrt{65}}{2*1}=\frac{6-4\sqrt{65}}{2} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+4\sqrt{65}}{2*1}=\frac{6+4\sqrt{65}}{2} $
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